Water Treatment: Settling, Filtration, Disinfection
Plain sedimentation and Stokes' law, overflow rate and detention time, coagulation and flocculation with velocity gradient, slow and rapid sand filters, softening and chlorination.
A conventional water treatment plant removes particles, then germs: screening → aeration → coagulation and flocculation → sedimentation → filtration → disinfection.
Sedimentation
Discrete particles settle at the Stokes' velocity:
v_s = g (G_s − 1) d²/(18 ν)
(valid for small particles, Re < 1).
An ideal settling tank removes all particles whose v_s is at least the surface overflow rate:
v₀ = Q/A (plan area A) — removal does not depend on depth.
- Particles with v_s < v₀ are removed in the fraction v_s/v₀.
- Detention time t = V/Q.
- Weir loading = Q/(weir length).
Coagulation and flocculation
- Coagulants (alum, ferric salts) neutralise the charge on colloids so they stick together. The dose is found by the jar test.
- Alum consumes alkalinity: Al₂(SO₄)₃·14H₂O + 3Ca(HCO₃)₂ → 2Al(OH)₃ + 3CaSO₄ + 6CO₂ + 14H₂O.
- Velocity gradient G = √(P/(μV)) (P = power input). Flash mixing: high G for seconds; flocculation: G ≈ 20–80 s⁻¹ for 20–40 minutes. Gt (dimensionless) is about 10⁴–10⁵.
Filtration
| Feature | Slow sand filter | Rapid sand filter |
|---|---|---|
| Rate | 2.4–4.8 m³/m²/day | ~ 100–150 m³/m²/day (about 30 times faster) |
| Main action | Biological layer (schmutzdecke) | Straining and adsorption |
| Cleaning | Scraping the top layer | Backwashing |
| Pre-treatment | Not needed for clear water | Coagulation needed |
Effective size D₁₀ and uniformity coefficient D₆₀/D₁₀ describe the filter sand. Backwash expands the bed by about 20–50%.
Softening and other processes
- Lime–soda process: lime removes carbonate hardness; soda ash removes non-carbonate hardness.
- Ion exchange (zeolite): removes all hardness, gives zero-hardness water.
- Defluoridation (Nalgonda technique), iron and manganese removal by aeration.
Disinfection
- Chlorine forms HOCl (strong disinfectant), which dissociates to OCl⁻ at high pH. Disinfection works best below pH about 7.5.
- Chlorine demand = applied − residual. Breakpoint chlorination: add chlorine until free residual appears after destroying ammonia compounds.
- Residual of 0.2 mg/L free chlorine at the consumer end is the usual target.
- Alternatives: ozone, UV.
Worked example
A tank treats 6 MLD with plan area 250 m² and depth 3 m.
- Overflow rate = 6000/250 = 24 m³/m²/day; detention time = 750/6000 × 24 = 3 hours.
Practice
A settling tank has an overflow rate of 30 m³/m²/day. A particle settles at 15 m/day. What percentage of such particles is removed?
Show answer and explanation
Answer: 50Fraction removed = v_s/v₀ = 15/30 = 50%.
A flocculator of volume 500 m³ receives 2.5 kW of power; μ = 10⁻³ Pa·s. What is the velocity gradient in s⁻¹?
Show answer and explanation
Answer: 70.71G = √(P/(μV)) = √(2500/0.5) = √5000 = 70.71 s⁻¹.
Chlorine is applied at 2.0 mg/L and the residual after contact is 0.3 mg/L. What is the chlorine demand in mg/L?
Show answer and explanation
Answer: 1.7Demand = applied − residual = 1.7 mg/L.
The main purification in a slow sand filter is due to:
Show answer and explanation
Answer: AThe schmutzdecke, a biological film on top of the sand, removes most impurities and bacteria.