Friction, Inclined Planes and Belt Friction
Static and kinetic friction, angle of friction and angle of repose, blocks on inclined planes, ladder problems, wedges and the belt friction equation T1/T2 = e^(μθ).
Friction is the force that resists sliding between two surfaces. GATE asks friction questions on blocks, inclines, ladders and belts; all follow from a few rules.
Laws of dry (Coulomb) friction
- Friction acts along the surface, opposite to the motion (or the tendency of motion).
- Before sliding, friction takes whatever value equilibrium needs, up to a limit: F ≤ μ_s N.
- At the point of sliding, F = μ_s N (limiting friction). While sliding, F = μ_k N, with μ_k slightly less than μ_s.
- Friction does not depend on the contact area.
Angle of friction φ: the angle between the normal reaction and the total reaction at limiting friction. tan φ = μ.
Angle of repose: the steepest incline on which a block stays at rest. It equals the angle of friction.
Block on an inclined plane
For a block of weight W on an incline at angle θ:
- Normal reaction N = W cos θ.
- Component pulling it down the slope = W sin θ.
- It stays at rest if W sin θ ≤ μ W cos θ, that is tan θ ≤ μ.
The force P parallel to the incline needed to push it up at constant speed: P = W(sin θ + μ cos θ). To just stop it sliding down: P = W(sin θ − μ cos θ).
Ladder against a wall
A ladder of length L and weight W leans on a rough floor (μ₁) and a wall (μ₂). Draw the FBD with N and F at both ends, take moments about the foot, and use F ≤ μN at each surface. For a uniform ladder with a smooth wall, the smallest angle θ with the floor at which it can stand is given by tan θ_min = 1/(2μ₁).
Belt friction
For a flat belt wrapped through angle θ (radians) on a pulley, at the point of slipping:
T₁/T₂ = e^(μθ), where T₁ is the tight-side tension.
Power transmitted = (T₁ − T₂) v. For a V-belt with groove angle 2β, replace μ by μ/sin β.
Worked example
A 100 N block rests on a 30° incline with μ = 0.25. Will it slide, and what force parallel to the slope pushes it up at constant speed?
- tan 30° = 0.577 > 0.25, so it slides if released.
- P = 100 (sin 30° + 0.25 cos 30°) = 100 (0.5 + 0.2165) = 71.65 N.
Practice
A block rests on an incline. The angle of repose is 20°. What is the coefficient of static friction? (Give 3 decimal places.)
Show answer and explanation
Answer: 0.364μ = tan(angle of repose) = tan 20° ≈ 0.364.
A belt has slack-side tension 100 N, μ = 0.3 and wrap angle π radians. What is the maximum tight-side tension in N? (Give 1 decimal place.)
Show answer and explanation
Answer: 256.6T₁ = T₂ e^(μθ) = 100 × e^(0.942) ≈ 256.6 N.
A 200 N block on a horizontal floor has μ = 0.4. A horizontal force of 50 N is applied. What is the friction force in N?
Show answer and explanation
Answer: 50Limiting friction is 0.4 × 200 = 80 N, more than 50 N, so the block stays at rest and friction is only 50 N.
Which statements about dry friction are true? (Select all that apply.)
Show answer and explanation
Answer: A, BFriction is independent of contact area, and kinetic friction is usually a little less than static.