Friction, Inclined Planes and Belt Friction

Static and kinetic friction, angle of friction and angle of repose, blocks on inclined planes, ladder problems, wedges and the belt friction equation T1/T2 = e^(μθ).

Friction is the force that resists sliding between two surfaces. GATE asks friction questions on blocks, inclines, ladders and belts; all follow from a few rules.

Laws of dry (Coulomb) friction

  • Friction acts along the surface, opposite to the motion (or the tendency of motion).
  • Before sliding, friction takes whatever value equilibrium needs, up to a limit: F ≤ μ_s N.
  • At the point of sliding, F = μ_s N (limiting friction). While sliding, F = μ_k N, with μ_k slightly less than μ_s.
  • Friction does not depend on the contact area.

Angle of friction φ: the angle between the normal reaction and the total reaction at limiting friction. tan φ = μ.

Angle of repose: the steepest incline on which a block stays at rest. It equals the angle of friction.

Block on an inclined plane

For a block of weight W on an incline at angle θ:

  • Normal reaction N = W cos θ.
  • Component pulling it down the slope = W sin θ.
  • It stays at rest if W sin θ ≤ μ W cos θ, that is tan θ ≤ μ.

The force P parallel to the incline needed to push it up at constant speed: P = W(sin θ + μ cos θ). To just stop it sliding down: P = W(sin θ − μ cos θ).

Ladder against a wall

A ladder of length L and weight W leans on a rough floor (μ₁) and a wall (μ₂). Draw the FBD with N and F at both ends, take moments about the foot, and use F ≤ μN at each surface. For a uniform ladder with a smooth wall, the smallest angle θ with the floor at which it can stand is given by tan θ_min = 1/(2μ₁).

Belt friction

For a flat belt wrapped through angle θ (radians) on a pulley, at the point of slipping:

T₁/T₂ = e^(μθ), where T₁ is the tight-side tension.

Power transmitted = (T₁ − T₂) v. For a V-belt with groove angle 2β, replace μ by μ/sin β.

Worked example

A 100 N block rests on a 30° incline with μ = 0.25. Will it slide, and what force parallel to the slope pushes it up at constant speed?

  • tan 30° = 0.577 > 0.25, so it slides if released.
  • P = 100 (sin 30° + 0.25 cos 30°) = 100 (0.5 + 0.2165) = 71.65 N.

Practice

GATE-styleNAT · numerical answer

A block rests on an incline. The angle of repose is 20°. What is the coefficient of static friction? (Give 3 decimal places.)

Show answer and explanationAnswer: 0.364

μ = tan(angle of repose) = tan 20° ≈ 0.364.

GATE-styleNAT · numerical answer

A belt has slack-side tension 100 N, μ = 0.3 and wrap angle π radians. What is the maximum tight-side tension in N? (Give 1 decimal place.)

Show answer and explanationAnswer: 256.6

T₁ = T₂ e^(μθ) = 100 × e^(0.942) ≈ 256.6 N.

GATE-styleNAT · numerical answer

A 200 N block on a horizontal floor has μ = 0.4. A horizontal force of 50 N is applied. What is the friction force in N?

Show answer and explanationAnswer: 50

Limiting friction is 0.4 × 200 = 80 N, more than 50 N, so the block stays at rest and friction is only 50 N.

GATE-styleMSQ · one or more correct answers

Which statements about dry friction are true? (Select all that apply.)

Show answer and explanationAnswer: A, B

Friction is independent of contact area, and kinetic friction is usually a little less than static.