Per-Unit System and Load Flow

Per-unit quantities and change of base, single-line diagrams, bus admittance matrix formation, bus types, Gauss-Seidel and Newton-Raphson load flow, and voltage control.

Large networks are analysed in per unit on common bases, and their steady-state operation is found by load flow (power flow) studies.

Per-unit system

  • Choose S_base (three-phase MVA) and V_base (line kV) in one zone; V_base in other zones follows the transformer ratios.
  • Z_base = V_base²/S_base; I_base = S_base/(√3 V_base).
  • Change of base: Z_new = Z_old (S_new/S_old)(V_old/V_new)².
  • Advantages: transformer impedances are the same on both sides, values fall in a narrow range, and √3 factors disappear.

Bus admittance matrix (Y_bus)

For a network with line admittances y_ij:

  • Diagonal Y_ii = sum of all admittances connected to bus i (including shunt charging).
  • Off-diagonal Y_ij = −y_ij (zero if not connected).
  • Y_bus is sparse and symmetric (without phase shifters). Z_bus = Y_bus⁻¹ is full.

Bus types

BusSpecifiedUnknown
Slack (swing)V, δ (= 0)P, Q
PV (generator)P, VQ, δ
PQ (load)P, QV, δ

Power flow equations

P_i − jQ_i = V_i* Σ Y_ij V_j

These are non-linear, so they are solved iteratively:

  • Gauss–Seidel: simple, little memory per iteration, but many iterations (convergence slows with system size); acceleration factor about 1.6.
  • Newton–Raphson: uses the Jacobian; quadratic convergence, few iterations (3–5) independent of size; standard for large systems.
  • Fast decoupled: uses P–δ and Q–V decoupling with constant matrices; very fast.
  • DC load flow: lossless, flat voltages, P = B′δ; linear and approximate.

Voltage and frequency control

  • Real power ↔ frequency (governors, load frequency control).
  • Reactive power ↔ voltage (generator excitation, tap-changing transformers, shunt capacitors and reactors, SVCs).

Worked example

A 50 MVA, 11 kV generator has X = 0.2 pu. On a 100 MVA, 11 kV base:

  • X_new = 0.2 × (100/50) × (11/11)² = 0.4 pu.

Practice

GATE-styleNAT · numerical answer

What is the base impedance (Ω) for 100 MVA and 132 kV? (Give 2 decimal places.)

Show answer and explanationAnswer: 174.24

Z_base = kV²/MVA = 17,424/100 = 174.24 Ω.

GATE-styleNAT · numerical answer

A bus connects to two lines with admittances −j5 and −j10 pu. What is the diagonal element Y_ii (imaginary part, in pu)?

Show answer and explanationAnswer: -15

Y_ii = −j5 − j10 = −j15 pu.

GATE-styleNAT · numerical answer

A 20 MVA, 33 kV transformer has X = 0.1 pu. What is its reactance on a 100 MVA, 33 kV base (pu)?

Show answer and explanationAnswer: 0.5

X_new = 0.1 × 100/20 = 0.5 pu.

GATE-styleMCQ · one correct answer

At a PV bus, the quantities specified are:

Show answer and explanationAnswer: B

A generator bus holds its real power output and voltage magnitude; Q and δ are found by the load flow.