Performance of Transmission Lines

Short, medium and long line models, ABCD constants, voltage regulation and efficiency, Ferranti effect, surge impedance loading, power transfer and reactive power compensation.

A line's model depends on its length. From the model we get the sending-end voltage, regulation, efficiency and the power the line can carry.

Line models

LineLength (50 Hz)Model
ShortUp to about 80 kmSeries impedance only
Medium80–250 kmNominal π (or T)
LongAbove 250 kmDistributed parameters (hyperbolic)

ABCD constants: V_S = A V_R + B I_R, I_S = C V_R + D I_R, with AD − BC = 1 (and A = D for symmetric lines).

  • Short line: A = D = 1, B = Z, C = 0.
  • Nominal π: A = D = 1 + YZ/2, B = Z, C = Y(1 + YZ/4).
  • Long line: A = cosh γl, B = Z_c sinh γl, C = sinh(γl)/Z_c.

Regulation and efficiency

  • Voltage regulation = (|V_R,no load| − |V_R,full load|)/|V_R,full load|, with V_R,NL = V_S/|A|.
  • Short line approximation: regulation ≈ I(R cos φ + X sin φ)/V_R (+ for lagging pf).
  • Efficiency = P_R/(P_R + losses).

Ferranti effect

On a lightly loaded or open long line, the charging current through the series inductance makes the receiving-end voltage higher than the sending-end voltage. Corrected with shunt reactors.

Surge impedance and SIL

  • Surge (characteristic) impedance Z_c = √(L/C) ≈ 400 Ω for overhead lines (about 40 Ω for cables).
  • Surge impedance loading SIL = V_L²/Z_c. At SIL, the line's reactive power generation and absorption balance, and the voltage profile is flat.
  • Velocity of propagation 1/√(LC) ≈ speed of light for overhead lines.

Power transfer

For a lossless line of reactance X:

P = (V_S V_R/X) sin δ

Maximum at δ = 90°. Reactive power flows from the higher voltage end to the lower; real power flows from the leading-angle end.

Compensation: series capacitors reduce X (raise power transfer); shunt capacitors support voltage under heavy load; shunt reactors limit voltage at light load. FACTS devices (SVC, STATCOM, TCSC) do this with electronics.

Worked example

A 400 kV line has Z_c = 400 Ω.

  • SIL = (400 × 10³)²/400 = 400 MW.

Practice

GATE-styleNAT · numerical answer

A 220 kV line has a surge impedance of 400 Ω. What is its SIL in MW?

Show answer and explanationAnswer: 121

SIL = V²/Z_c = (220 × 10³)²/400 = 121 MW.

GATE-styleNAT · numerical answer

A short line has R = 5 Ω and X = 10 Ω and carries 100 A at 0.8 pf lagging, with V_R = 11 kV per phase. What is its approximate regulation in percent? (Give 3 decimal places.)

Show answer and explanationAnswer: 9.091

Reg ≈ I(R cos φ + X sin φ)/V_R = 100 × (4 + 6)/11,000 = 0.0909 = 9.091%.

GATE-styleNAT · numerical answer

A lossless line has V_S = V_R = 1 pu and X = 0.4 pu. What is the maximum power it can transfer in pu?

Show answer and explanationAnswer: 2.5

P_max = V_SV_R/X = 2.5 pu.

GATE-styleMCQ · one correct answer

The Ferranti effect occurs on a long line when it is:

Show answer and explanationAnswer: A

The capacitive charging current flowing through the line inductance raises the receiving-end voltage.