PN Junction, Zener, LED and Photodiode

Built-in potential, depletion width and junction capacitance, ideal diode equation, breakdown (Zener and avalanche), diffusion capacitance, LEDs, photodiodes and solar cells.

The PN junction is the building block of diodes, transistors and optoelectronic devices.

Equilibrium

  • At the junction, diffusion leaves a depletion region of fixed ions and a built-in field.
  • Built-in potential: V_bi = V_T ln(N_A N_D/n_i²).
  • Depletion width W = √(2ε(V_bi − V)/q × (1/N_A + 1/N_D)); it extends mostly into the lightly doped side: x_n N_D = x_p N_A.
  • Reverse bias widens W; forward bias narrows it. W ∝ √(V_bi + V_R).

Current

I = I_s(e^(V/(ηV_T)) − 1)

  • I_s depends on n_i², so it rises very fast with temperature (doubles about every 10 °C for Si).
  • A 60 mV increase in forward voltage multiplies the current by about 10 (at η = 1).
  • At fixed current, V_D falls by about 2 mV/°C.

Capacitance

  • Junction (depletion) capacitance C_j = εA/W, dominant in reverse bias: C_j ∝ (V_bi + V_R)^(−1/2) for an abrupt junction. Used in varactor diodes for tuning.
  • Diffusion capacitance C_d = τ I/V_T, dominant in forward bias.

Breakdown

  • Zener breakdown: heavily doped junctions, thin depletion region, tunnelling; below about 5 V; negative temperature coefficient.
  • Avalanche breakdown: lightly doped, impact ionisation; above about 6 V; positive temperature coefficient.
  • Around 5–6 V the two effects cancel, giving the most temperature-stable Zeners.

Optoelectronic devices

  • LED: forward-biased direct-gap junction; photon wavelength λ (µm) = 1.24/E_g (eV).
  • Photodiode: reverse-biased; light creates carriers that add a current proportional to light intensity. PIN and avalanche photodiodes are faster and more sensitive.
  • Solar cell: unbiased junction in the fourth quadrant; open-circuit voltage, short-circuit current and fill factor describe it.

Worked example

A Si junction has N_A = 10¹⁷ and N_D = 10¹⁶ cm⁻³, n_i = 10¹⁰ cm⁻³, V_T = 0.0259 V.

  • V_bi = 0.0259 ln(10³³/10²⁰) = 0.0259 × 29.93 = 0.775 V.
  • The depletion region extends 10 times further into the n side than the p side.

Practice

GATE-styleNAT · numerical answer

What wavelength (µm) does a GaAs LED with E_g = 1.42 eV emit? (Give 3 decimal places.)

Show answer and explanationAnswer: 0.873

λ = 1.24/E_g = 1.24/1.42 = 0.873 µm (near infrared).

GATE-styleNAT · numerical answer

A diode carries 1 mA. By roughly what factor does its current rise if the forward voltage increases by 60 mV (η = 1, V_T = 26 mV)? (Give 2 decimal places.)

Show answer and explanationAnswer: 10.05

I₂/I₁ = e^(ΔV/V_T) = e^(2.308) = 10.05.

GATE-styleNAT · numerical answer

A varactor has 40 pF at 4 V reverse bias. Ignoring V_bi, what is its capacitance (pF) at 16 V? (Abrupt junction.)

Show answer and explanationAnswer: 20

C ∝ V^(−1/2): 40 × √(4/16) = 20 pF.

GATE-styleMCQ · one correct answer

A Zener diode rated 3.3 V breaks down mainly by:

Show answer and explanationAnswer: A

Low-voltage Zeners are heavily doped and break down by tunnelling, whose voltage falls as temperature rises.