Integration
Standard integrals, substitution and integration by parts, properties of definite integrals (symmetry and the a − x trick), areas between curves, and checking answers with Simpson's rule.
Standard integrals
| f(x) | ∫ f(x) dx |
|---|---|
| xⁿ (n ≠ −1) | xⁿ⁺¹/(n + 1) |
| 1/x | ln |x| |
| eˣ, aˣ | eˣ, aˣ/ln a |
| sin x, cos x | −cos x, sin x |
| sec² x | tan x |
| 1/(1 + x²) | tan⁻¹ x |
| 1/√(1 − x²) | sin⁻¹ x |
(Each plus a constant C.)
Techniques
- Substitution: if the integrand contains g(x) and g′(x), put u = g(x). Example: ∫ 2x eˣ² dx = eˣ² + C.
- Integration by parts: ∫ u dv = uv − ∫ v du. Choose u in the order ILATE (inverse trigonometric, logarithmic, algebraic, trigonometric, exponential). Example: ∫₀¹ x eˣ dx = [x eˣ]₀¹ − ∫₀¹ eˣ dx = e − (e − 1) = 1.
- Partial fractions for rational functions; trigonometric identities such as sin² x = (1 − cos 2x)/2.
Properties of definite integrals
| Property | Statement |
|---|---|
| Reversing limits | ∫ab f = −∫ba f |
| Splitting | ∫ab f = ∫ac f + ∫cb f |
| The a − x property | ∫₀ᵃ f(x) dx = ∫₀ᵃ f(a − x) dx |
| Odd function on [−a, a] | ∫₋ₐᵃ f = 0 |
| Even function on [−a, a] | ∫₋ₐᵃ f = 2∫₀ᵃ f |
| Periodic with period T | ∫₀ⁿᵀ f = n∫₀ᵀ f |
The a − x property solves integrals that look hard. Let I = ∫₀^(π/2) sin x / (sin x + cos x) dx. Replacing x by π/2 − x swaps sin and cos, so I = ∫₀^(π/2) cos x / (cos x + sin x) dx. Adding the two forms: 2I = ∫₀^(π/2) 1 dx = π/2, so I = π/4.
Symmetry: ∫₋₁¹ x³ cos x dx = 0, because x³ cos x is odd.
Areas
The area between y = f(x) and y = g(x) from a to b (with f ≥ g) is ∫ₐᵇ (f(x) − g(x)) dx. Between y = x and y = x², which meet at x = 0 and x = 1: ∫₀¹ (x − x²) dx = 1/2 − 1/3 = 1/6.
When a function changes sign, area and integral differ: ∫₀³ |x − 1| dx splits at x = 1 into 1/2 + 2 = 2.5.
Checking answers numerically
Simpson's rule approximates ∫ₐᵇ f by fitting parabolas through equally spaced points: (h/3)[f(x₀) + 4f(x₁) + 2f(x₂) + 4f(x₃) + … + f(xₙ)] with n even. It is very accurate for smooth functions, and a good way to check a hand computation:
import math
def simpson(f, a, b, n=1000):
h = (b - a) / n
total = f(a) + f(b) + sum((4 if i % 2 else 2) * f(a + i * h) for i in range(1, n))
return total * h / 3
checks = [
("x e^x on [0, 1]", lambda x: x * math.exp(x), 0, 1, 1),
("sin^2 x on [0, pi/2]", lambda x: math.sin(x) ** 2, 0, math.pi / 2, math.pi / 4),
("x sin x on [0, pi]", lambda x: x * math.sin(x), 0, math.pi, math.pi),
("sin/(sin+cos) on [0, pi/2]", lambda x: math.sin(x) / (math.sin(x) + math.cos(x)), 0, math.pi / 2, math.pi / 4),
("x - x^2 on [0, 1]", lambda x: x - x * x, 0, 1, 1 / 6),
]
for name, f, a, b, exact in checks:
print(f"{name:28} Simpson {simpson(f, a, b):.6f} exact {exact:.6f}")
x e^x on [0, 1] Simpson 1.000000 exact 1.000000 sin^2 x on [0, pi/2] Simpson 0.785398 exact 0.785398 x sin x on [0, pi] Simpson 3.141593 exact 3.141593 sin/(sin+cos) on [0, pi/2] Simpson 0.785398 exact 0.785398 x - x^2 on [0, 1] Simpson 0.166667 exact 0.166667
Trapezoidal rule: (h/2)[f(x₀) + 2f(x₁) + … + 2f(xₙ₋₁) + f(xₙ)]. Its error is O(h²), compared with O(h⁴) for Simpson's rule; the trapezoidal rule is exact for straight lines, Simpson's rule for polynomials up to degree 3.
Practice questions
What is ∫₀^π x sin x dx? Give the answer to two decimal places.
Show answer and explanation
Answer: 3.14By parts with u = x, dv = sin x dx: [−x cos x]₀^π + ∫₀^π cos x dx = π + 0 = π ≈ 3.14.
What is ∫₋₂² (x⁵ + 3x²) dx?
Show answer and explanation
Answer: 16x⁵ is odd, so its integral over [−2, 2] is 0. 3x² is even: 2∫₀² 3x² dx = 2[x³]₀² = 16.
What is the area enclosed between y = x² and y = 2x? Give the answer to two decimal places.
Show answer and explanation
Answer: 1.33The curves meet at x = 0 and x = 2, and 2x ≥ x² between them: ∫₀² (2x − x²) dx = [x² − x³/3]₀² = 4 − 8/3 = 4/3 ≈ 1.33.
Which statements are true? (Select all that apply.)
Show answer and explanation
Answer: A, B, DOdd functions cancel over symmetric intervals, and substituting x → a − x maps [0, a] onto itself. The integral of a product is not the product of integrals (try f = g = x on [0, 1]: 1/3 versus 1/4). Simpson's rule happens to integrate cubics exactly.