Resonance, Coupled Coils and Three-Phase

Series and parallel resonance, quality factor and bandwidth, mutual inductance and dot convention, balanced star and delta systems, line and phase quantities, and the two-wattmeter method.

This lesson covers three AC topics that GATE EE tests every year: resonance, magnetically coupled coils, and three-phase circuits.

Series resonance

At ω₀ = 1/√(LC), X_L = X_C, so Z = R (minimum) and the current is maximum, in phase with the voltage.

  • Quality factor Q = ω₀L/R = 1/(ω₀CR) = (1/R)√(L/C).
  • Bandwidth BW = ω₀/Q = R/L (rad/s). Half-power frequencies: ω₁ω₂ = ω₀².
  • Voltage across L or C at resonance = Q × source voltage (voltage magnification).

Parallel resonance

An ideal parallel LC tank has maximum impedance (infinite) at ω₀; with a coil of resistance R, ω₀ = √(1/(LC) − R²/L²) and the dynamic impedance is L/(CR). Current magnification instead of voltage.

Coupled coils

  • Mutual inductance M = k√(L₁L₂), with coupling coefficient 0 ≤ k ≤ 1.
  • Series aiding: L = L₁ + L₂ + 2M; series opposing: L₁ + L₂ − 2M.
  • Dot convention: current entering both dots gives aiding fluxes (+M).
  • Ideal transformer: V₁/V₂ = N₁/N₂, and an impedance Z_L on the secondary looks like (N₁/N₂)² Z_L from the primary.

Balanced three-phase systems

ConnectionLine voltageLine current
Star (Y)V_L = √3 V_ph (leads by 30°)I_L = I_ph
Delta (Δ)V_L = V_phI_L = √3 I_ph (lags by 30°)
  • Total power P = √3 V_L I_L cos φ (φ = phase angle of the load impedance).
  • A balanced delta load Z_Δ is equivalent to a star load Z_Δ/3.
  • Phase sequence ABC: V_B lags V_A by 120°.

Two-wattmeter method (three-wire balanced load):

  • P = W₁ + W₂.
  • tan φ = √3 (W₁ − W₂)/(W₁ + W₂).
  • At pf 0.5, one wattmeter reads zero; below 0.5, one reads negative.

Worked example

A balanced star load of (8 + j6) Ω per phase on a 400 V line supply.

  • V_ph = 400/√3 = 230.9 V; |Z| = 10 Ω; I = 23.09 A; pf = 0.8.
  • P = √3 × 400 × 23.09 × 0.8 = 12.8 kW.

Practice

GATE-styleNAT · numerical answer

A series RLC circuit has R = 10 Ω, L = 0.1 H and C = 10 µF. What is its quality factor?

Show answer and explanationAnswer: 10

Q = (1/R)√(L/C) = 0.1 × √10,000 = 10.

GATE-styleNAT · numerical answer

In the two-wattmeter method, W₁ = 3 kW and W₂ = 1 kW. What is the power factor? (Give 3 decimal places.)

Show answer and explanationAnswer: 0.756

tan φ = √3 × 2/4 = 0.866, so φ = 40.9° and cos φ = 0.756.

GATE-styleNAT · numerical answer

Two coils of 4 mH and 9 mH have k = 0.5. What is the total inductance (mH) in series aiding?

Show answer and explanationAnswer: 19

M = 0.5√36 = 3 mH; L = 4 + 9 + 6 = 19 mH.

GATE-styleNAT · numerical answer

In the worked example, what is the total power in kW? (Give 1 decimal place.)

Show answer and explanationAnswer: 12.8

P = 3I²R = 3 × 23.09² × 8 = 12,800 W = 12.8 kW.