Compass, Theodolite and Traversing
Bearings (WCB and quadrantal), magnetic declination and local attraction, theodolite measurement, latitudes and departures, closing error, Bowditch and transit rules, and area by coordinates.
Angles and directions locate points horizontally. A traverse is a series of lines whose lengths and directions are measured to build a control framework.
Bearings
- Whole circle bearing (WCB): 0°–360° clockwise from north.
- Quadrantal (reduced) bearing: N or S, angle (0–90°), E or W. Example: WCB 210° = S 30° W.
- Back bearing = fore bearing ± 180°.
- Included angle between two lines = difference of their bearings (taken properly).
- True bearing = magnetic bearing ± declination (+ for east declination).
- Local attraction (from nearby iron) is detected when the fore and back bearings of a line differ by other than 180°; correct from a station free of it.
Theodolite
- Measures horizontal and vertical angles to seconds of arc.
- Face left and face right observations, averaged, eliminate collimation, trunnion axis and index errors.
- Methods: repetition (accumulate an angle several times) and reiteration (several angles from one station).
Traverse computations
For each line of length L and bearing θ:
- Latitude = L cos θ (northing +, southing −).
- Departure = L sin θ (easting +, westing −).
For a closed traverse, Σ latitudes = 0 and Σ departures = 0 ideally. In practice:
- Closing error e = √((ΣL)² + (ΣD)²), with direction tan⁻¹(ΣD/ΣL).
- Relative precision = e/perimeter (for example 1 in 5000).
- Angular check: sum of interior angles = (2n − 4) × 90°.
Balancing:
- Bowditch's (compass) rule: correction to a line ∝ its length (when angles and distances are equally precise).
- Transit rule: correction ∝ the line's latitude or departure (when angles are more precise than distances).
Area from coordinates
A = ½ |Σ (xᵢ yᵢ₊₁ − xᵢ₊₁ yᵢ)| (the shoelace formula). Areas of irregular boundaries: trapezoidal rule or Simpson's rule (odd number of ordinates).
Worked example
A closed traverse has ΣL = +0.30 m and ΣD = −0.40 m with a perimeter of 2500 m.
- e = √(0.09 + 0.16) = 0.5 m; precision = 0.5/2500 = 1 in 5000.
Practice
Convert the whole circle bearing 300° to a quadrantal bearing.
Show answer and explanation
Answer: A300° lies in the NW quadrant: 360° − 300° = 60°, so N 60° W.
A line 100 m long has a WCB of 60°. What is its departure in m? (Give 2 decimal places.)
Show answer and explanation
Answer: 86.6Departure = L sin θ = 100 × 0.866 = 86.60 m (east).
What should be the sum of the interior angles of a closed traverse with 6 sides, in degrees?
Show answer and explanation
Answer: 720(2n − 4) × 90° = 8 × 90° = 720°.
A triangle has vertices (0, 0), (40, 0) and (40, 30) in metres. What is its area in m²?
Show answer and explanation
Answer: 600Shoelace: ½|0 + 1200 + 0| = 600 m².